find the general solution of 2 cos x -1 =0
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⇒ cos x = cos (2nπ - π4), Where n ∈ I (i.e., n = 0, ± 1, ± 2, ± 3,…….) Therefore, the general solutions of equation cos x = 1√2 are the infinite sets of value of x given in (i) and (ii). Hence general solution of √2 cos x - 1 = 0 is x = 2nπ ± π4, n ∈ I.
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cos x = cos (2nπ - π4), Where n ∈ I (i.e., n = 0, ± 1, ± 2, ± 3,…….) Therefore, the general solutions of equation cos x = 1√2 are the infinite sets of value of x given in (i) and (ii). Hence general solution of √2 cos x - 1 = 0 is x = 2nπ ± π4, n ∈ I.
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