Question

Find the general solution of 2cos^2x − 3sinx = 0​

Answer 1

Answer:

POSSIBLE VALUES FOR sin x = 2 , 1/2

2cos 2 x + 3sinx=0

⇒2(1−sin  2  x)+3sinx=0

⇒2(sin  2  x)−3sinx−2=0

⇒2(sin  2 x)−4sinx+sinx−2=0  

⇒2sinx(sinx−2)+(sinx−2)=0  

⇒(sinx−2)+(2sinx+1)=0  

⇒sin x=2,sin x=−  1/2

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Answer 2

Answer:

ok

pihu

class 8

age 13

it's my intro

BTW yours