Find the general solution of 2cos^2x+3sinx=0
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Answered by
193
2cos^2x+3sinx=0
2(1-sin^2x)+3sinx=0
2-2sin^2x +3sinx=0
2sin^2x -3sinx -2=0
2sin^2x -4sinx+sinx-2=0
2sin x(sin x-2)+1(sinx-2)=0
(sin x -2)(2sin x+1)=0
sin x - 2=0 or 2 sin x+1=0
sin x =2 or sin x = -1/2
2(1-sin^2x)+3sinx=0
2-2sin^2x +3sinx=0
2sin^2x -3sinx -2=0
2sin^2x -4sinx+sinx-2=0
2sin x(sin x-2)+1(sinx-2)=0
(sin x -2)(2sin x+1)=0
sin x - 2=0 or 2 sin x+1=0
sin x =2 or sin x = -1/2
Answered by
28
Answer:
Step-by-step explanation:
2cos^2x+3sinx=0
2(1-sin^2x)+3sinx=0
2-2sin^2x +3sinx=0
2sin^2x -3sinx -2=0
2sin^2x -4sinx+sinx-2=0
2sin x(sin x-2)+1(sinx-2)=0
(sin x -2)(2sin x+1)=0
sin x - 2=0 or 2 sin x+1=0
sin x =2 or sin x = -1/2
Hope this may help u
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