Math, asked by lahari4612, 4 months ago

find the general solution of (4D²+4D+1)=0

Answers

Answered by simranshaw6289

0

Answer:

(4D²+4D+1)=0

4D²+4D= -1

4D(D+1)= -1

D+1 = -4D

1 = -4D -D

-5D =1

D = 1/-5

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