Math, asked by pranjalis593, 11 months ago

Find the general.solution of 4sin²x-3=0

Answers

Answered by anujyadav3124
9

Answer:

4( {sin}^{2} x - 3 )= 0 \\  \\ 4( {cos}^{2} x- 1) - 3 = 0 \\  \\ 4 {cos}^{2} x - 4 - 3 = 0 \\  \\ 4 {cos}^{2} x - 7 = 0 \\  \\ 4 {cos}^{2} x = 7 \\  \\  {cos}^{2} x =  \frac{7}{4}  \\  \\ cosx =  \frac{ \sqrt{7} }{ \sqrt{4} }  \\  \\ cosx =  \frac{ \sqrt{7} }{2} .

here is your answer.

Step-by-step explanation:

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