find the general solution of Cos 3∅ = to cos 2∅
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Answer:
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Step-by-step explanation:
cos3x−cos2x=0
−2sin(
2
3x+2x
)sin(
2
3x−2x
)=0
sin(
2
5x
)sin(
2
x
)=0
∴sin(
2
5x
)=0
(
2
5x
)=nπ
∴x=(
5
2nπ
)
∴sin(
2
x
)=0
(
2
x
)=nπ
∴x=2nπ
combiningbothresult
x=(
5
2nπ
)
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