Question

Find the general solution of equation root3sec2x=2

Answer 1

$given \: that \: \sqrt{3} \sec(2x) = 2 \\ then \: \\ \sqrt{3} \sec(2x) = 2 \\ \sec(2x) = 2 \div \sqrt{3} \\ we \: know \: that \: \sec( 30) = 2 \div \sqrt{3} \\ so \: 2x = 30 \\ x = 30 \div 2 \\ x = 15$
hope this helps you