Math, asked by Samstans, 7 months ago

Find the general solution of sec²x=1-tan²x

Answers

Answered by rakhibansode1582
0

Answer:

This are the formulae::

 1) \:  { \sec }^{2} x = 1  +   { \tan}^{2} x \\ 2) \:  { \sec}^{2} x  - 1 =   { \tan }^{2} x \\ 3) \:  { \sec}^{2}x -  { \tan }^{2} x = 1

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