Math, asked by rahulverm640, 17 hours ago

Find the general solution of sin sin3 sin5 0​

Answers

Answered by thor3899
0

Answer:

From the triangle ABC

Consider ∠A=61

In a triangle

∠A+∠∠B+∠C=180

Substituting the values

61

+∠B+∠C=180

By further calculation

∠B+∠C=180

–61

=119

∠B:∠C=1

2

1

:1

3

1

=3/2:4/3

Taking LCM

∠B:∠C=9:8/6

∠B:∠C=9:8

Consider ∠B=9x and ∠C=8x

Substituting the values

9x+8x=119

17x=119

x=119

/17=7

So we get

∠B=9x=9×7

=63

∠C=8x=8×7

=56

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