Find the general solution of sin sin3 sin5 0
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Answer:
From the triangle ABC
Consider ∠A=61
∘
In a triangle
∠A+∠∠B+∠C=180
∘
Substituting the values
61
∘
+∠B+∠C=180
∘
By further calculation
∠B+∠C=180
∘
–61
∘
=119
∘
∠B:∠C=1
2
1
:1
3
1
=3/2:4/3
Taking LCM
∠B:∠C=9:8/6
∠B:∠C=9:8
Consider ∠B=9x and ∠C=8x
Substituting the values
9x+8x=119
∘
17x=119
∘
x=119
∘
/17=7
∘
So we get
∠B=9x=9×7
∘
=63
∘
∠C=8x=8×7
∘
=56
∘
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