Question

find the general solution of tan 2theeta=0​

Answer 1

Answer:

$\tan2(θ) = 0$

$general \: solution \: if \: \tan(θ) = \tan( \alpha )$

$θ= n\pi + or - \alpha$

$\tan2(θ) = \tan(0)$

$so \: 2θ = n\pi + 0$

$2θ = n\pi$

$= > θ = \frac{n\pi}{2}$

This is the general solution for tan2θ=0