Find the general solution of the equation :
cos x + cos 3x - 2 cos 2x = 0
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Answer:
cos3x+cosx-2cos2x=0
(cos3x+cosx)-2cos2x=0
Using formula for cosx+cosy
cos3x+cosx = 2cos[(3x+x)/2].cos[(3x-x)/2]
=2cos2x.cosx
Putting this in above eqn
2cos2x.cosx-2cos2x=0
cos2x(cosx-1)=0
Solving for general solutions,
For cos2x=0
x=(2n+1)π/4, n∈Z.
For cosx-1=0
x=2nπ, n∈Z.
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