Math, asked by santhosh2004cgm, 10 months ago

find the general solution of the equation cos3x/2=0​

Answers

Answered by DevendraLal
4

The general solution of the equation cos3x/2=0​ is (2n+1)π/2

As we all know that the value of the Cos x is 0 at the value of x as:

  • π/2, 3π/2, 5π/2............

As you can clearly see that π has the odd coefficient in each case,

The notation for the odd numbers is (2n+1)

So the general solution of cos3x/2=0 is (2n+1)π/2

Answered by kinggrogu64
4

Answer:

Step-by-step explanation:

cos 3x/2  = 0

cos 3x/2 = cos\frac{\pi }{2}

\frac{3x}{2}  = (2n+1) \frac{\pi }{2} , where, n = 0, ± 1, ± 2, ± 3, …….

3x = (2n + 1) \pi , where, n = 0, ± 1, ± 2, ± 3, …….

Therefore, the general solution of the trigonometric equation cos 3x = 0 is

x = (2n + 1) \frac{\pi }{3}  , where, n = 0, ± 1, ± 2, ± 3, …….

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