Find the general solution of the equation cosx+cos3x-2.cos 2x=0.
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Answer:
x = 2xπ
Step-by-step explanation:
=cosx+(4cos 3x−3cosx)−2(2cos2x−1)=0
=cosx+4cos 3 x−3cosx−4cos 2x+2=0
=4cos 3 x−4cos 2 x−2cosx+2=0
=4cos 2x(cosx−1)−2(cosx−1)=0
=(4cos 2 x−2)(cosx−1)=0
=(2cos 2x−1)(cosx−1)=0
∴cos 2
x=1/2
or cos 2
x=cos 2(π/3)
∴x=xπ±π/3
and if cosx−1=0
cosx=1
cosx=cos0
∴x=2xπ
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