find the general solution of the following equation
3tan x + cot x = 5 cosec x
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hey dude.......
ur answer is here.....!!!!!!!!
3tanx+cotx= 5cosecx
3sinx/cosx+cosx/sinx= 5/sinx
3sin 2 x+cos 2 x= 5cosx
3-3cos 2x+cos 2 x= 5cosx
3-2cos 2x=5cosx
2cos 2x+5cosx-3= 0
2cos 2x+6cosx-cosx-3=0
2cosx(cosx+3)+(-1)(cosx+3)=0
Cosx= -3, or (1/2)
value of cosx always lies between -1 & 1..
there fore,,
cosx=½
thanks..
..!
ur answer is here.....!!!!!!!!
3tanx+cotx= 5cosecx
3sinx/cosx+cosx/sinx= 5/sinx
3sin 2 x+cos 2 x= 5cosx
3-3cos 2x+cos 2 x= 5cosx
3-2cos 2x=5cosx
2cos 2x+5cosx-3= 0
2cos 2x+6cosx-cosx-3=0
2cosx(cosx+3)+(-1)(cosx+3)=0
Cosx= -3, or (1/2)
value of cosx always lies between -1 & 1..
there fore,,
cosx=½
thanks..
..!
raahul072:
sry dude i forget to send u attached pic
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