Question

Find the general solution of y" + 16y = 0.​

Answer 1

Answer:

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YOUR ANSWER =>

The characteristic equation is

R^2 + 16 = 0,

which has solutions R = 0 +/—4i. This gives a general solution of the form

y(t) = e^(alpha*t)*[cos(beta*t) + sin(beta*t)],

where alpha = 0 and beta = 4.

So,

y(t) = c_1*cos(4t) + c_2*sin(4t).

Answer 2

y+16y=0

-16y+16y=0

this is the right answer