Question

find the general solution tanthita is equal to -root 3
​

Answer 1

Answer:

tanθ+

3

=0

⇒tanθ=−

3

⇒tanθ=tan(π−

3

π

)0rtan(2π−

3

π

)

commonly it can be written as

tanθ=tan(nπ−

3

π

)

⇒θ=(nπ−

3

π

)

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