Question

Find the general solutions of each of the following equations:
i.cot 4x =-1
​

Answer 1

$\cot(4x) = - 1 \\ \\ \cot(4x) = \cot( \frac{3\pi}{4} )$

$\bf {Since , cot \theta=cot \alpha ; \theta =n\pie+\alpha,n \in Z}$

$4x = n\pi + \frac{3\pi}{4}$

$\bf {the \: required\: general\: solution\: is \:x = \frac{n\pi}{4} + \frac{3\pi}{16}}$

Answer 2

Answer:

4x=-1

X=-1/4

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