Question

find the general term and 23rd term of the sequence 3,1,-1,-3........ .​

Answer 1

Step-by-step explanation:

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Answer 2

The correct answer is "a₂₃= -41".

Step-by-step explanation:

$The \ given \ series \ is:\\3,1,-1,-3...\\Now,\\The \ first \ term,a,a_{1} =3\\The \ second \ term,a_{2}=1 Difference,d =a_{2}-a_{1}=1-3=-2\\As \ we \ know,\\a_{n}=a+(n-1)d\\ a_{n}=3+(n-1)(-2)\\a_{n}=3-2n+2\\a_{n}=5-2n...(General \ term)\\Now,\\a_{23}=5-2(23)\\a_{23}=5-46\\a_{23}=-41$

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