Math, asked by Pranahu771, 9 months ago

find the general term in expansion of (x^2-y)^6

Answers

Answered by Heidi321

1

Answer:

x¹²-2x⁶y³+y⁶=0

Step-by-step explanation:

(x²-y)⁶

=(x¹²-y⁶)

=(x⁶-y³)²

=x¹²-2(x⁶)(y³)+y⁶

=x¹²-2x⁶y³+y⁶

∴The general term is x¹²-2x⁶y³+y⁶=0.

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