find the general term in expansion of (x^2-y)^6
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Answer:
x¹²-2x⁶y³+y⁶=0
Step-by-step explanation:
(x²-y)⁶
=(x¹²-y⁶)
=(x⁶-y³)²
=x¹²-2(x⁶)(y³)+y⁶
=x¹²-2x⁶y³+y⁶
∴The general term is x¹²-2x⁶y³+y⁶=0.
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