find the general term of ap by x+ b,x3b,x+5b
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(I method)
The Given Series : x+b, x+3b, x + 5b,...
This is an A.P.
∴ First Term, a = x+b
Difference, d = x+3b - (x+b) = x+3b - x-b= 2b
Now, The General Term ,
= a+(n-1)d
= x+b+(n-1)2b
= x+b+(2n-2)b
= x+b(1+2n-2)
= x+b(2n-1)
or. (II method)
a = x+b d = second term - first term
= x +3b -x - b
= 2b
tn = a + (n-1)d
= x+b+(n-1)2b
= x +b+2nb-2b
= x-b+2nb
= x+b(2n-1)
Hope this will help you.... ✌
The Given Series : x+b, x+3b, x + 5b,...
This is an A.P.
∴ First Term, a = x+b
Difference, d = x+3b - (x+b) = x+3b - x-b= 2b
Now, The General Term ,
= a+(n-1)d
= x+b+(n-1)2b
= x+b+(2n-2)b
= x+b(1+2n-2)
= x+b(2n-1)
or. (II method)
a = x+b d = second term - first term
= x +3b -x - b
= 2b
tn = a + (n-1)d
= x+b+(n-1)2b
= x +b+2nb-2b
= x-b+2nb
= x+b(2n-1)
Hope this will help you.... ✌
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