Science, asked by vishalmonurana, 8 months ago

*Find the genotype of Fi progeny a)mother homozygous for 'A' blood group and father 'O' blood group. b)Mother 'AB' blood group and father heterozygous for 'B' blood group.

Answers

Answered by sulabhkaura58
1

Answer:

A parent with A blood group can have two possible genotypes: “I

A

I

A

” and “I

A

I

O

”; similarly parent with B blood group can have two possible genotypes: “I

B

I

B

” and “I

B

I

O

”. If both the parents are homozygous (I

A

I

A

x I

B

I

B

) , all of their children will have AB blood group. But if father is heterozygous (I

A

I

O

”) and mother is homozygous (I

B

I

B

); the total different types of possible combinations by three alleles (I

A

, I

B

and I

O

) will be (I

A

I

B

and I

B

I

O

). But if mother is heterozygous (I

B

I

O

) and father is homozygous (I

A

I

A

); the total different types of possible combinations by three alleles (I

A

, I

B

and I

O

) will be (I

A

I

B

and I

B

I

O

).

Cross 1

Parent generation : I

A

I

A

x (I

B

I

B

)

Gametes :

I

A

I

A

-->

(I

A

I

B

)

I

A

I

A

I

B

I

A

I

B

I

A

I

B

I

B

I

A

I

B

I

A

I

B

F

1

generation phenotypic ratio = All AB group

Cross 2

Parent generation: I

A

I

O

X (I

B

I

B

)

Gametes

I

A

I

O

-->

I

B

I

B

I

A

I

O

I

B

I

A

I

B

I

B

I

O

I

B

I

A

I

B

I

B

I

O

F

1

generation phenotypic ratio = 1 AB group : 1 B group

Cross 3

Parent generation: I

A

I

A

X (I

B

I

O

)

Gametes

I

A

I

A

-->

I

B

I

B

I

A

I

A

I

B

I

A

I

B

I

A

I

B

I

O

I

A

I

O

I

A

I

O

F

1

generation phenotypic ratio = 1 AB group : 1 A group

Cross 4

Parent generation: I

A

I

O

X (I

B

I

O

)

Gametes :

I

A

I

O

-->

I

B

I

O

I

A

I

O

I

B

I

A

I

B

I

B

I

O

I

O

I

A

I

O

I

O

I

O

F

1

generation phenotypic ratio = 1 AB group : 1 B group : 1 A group : 1 O group

Thus, the correct answer is option D.

Answered by rakeshamin8246
2

Answer:

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Explanation:

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