Question

Find the geometric mean of first 5 terms of the geometric progression for which

$a_{n} = \frac{2.3}{5} ^{n}$

Where n belongs to N. ​

Answer 1

Here.

a1=

${ { \frac{2.3}{5} } }^{1}$

a5=

${ \frac{2.3}{5} }^{5}$

Geometric mean is:

$\sqrt{a1 \times a5} \\ = \sqrt{( { \frac{2.3}{5} )}^{1} \times { (\frac{2.3}{5}) }^{5} } \\ = \sqrt{ { \frac{2.3}{5} }^{6} } \\ = \sqrt{ { \frac{2.3}{5} }^{3} } \\ = a3$

Hope i get it right....

Regards;

Leukonov/Olegion.