Question

Find the geometric progression with the 4th term =54 and the 7th term=1458

Answer 1

$t7 \div t4 = a {r}^{6} \div a{r}^{3 } = r^{3}$
so r^3 = 1458/54 = 27
so r = 3
now ar^3 = 54 so a= 54/27 = 2
so the gp is
2 , 2×3 , 2× 3^2 ..... 2× 3^n
hope its worth a brainliest.

Answer 2

hey mate here is ur answer....