Question

Find the Gibbs energy change of the cell at 298K. 3Cr |Cr3+ (0.1M)|| Cu2+(0.01M) + |Cu. Given E° Cr3+ / Cr = – 0.75V, Cu2+/Cu = +0.34V, F = 96500C.​

Answer 1

Answer:

4

Explanation:

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Answer 2

Answer:

Cr ------Cr+3 +3e-

Cu+2 +2e- ----Cu

E=E0 +.059/n log(Cu+2/Cr+3)

=.34+.75 +.059/6log(.01/.1)

=1.09+.059/6log.1

=1.08

deltaG=-nFE

=-6*96500*1.08

=-625.32KJ