Question

Find the given sum:
1² + 3² + 5² + 7² + ...upto n terms

Answer 1

since n goes up to Infinity... these are positive no. therefore the answer goes up to +infinity

Answer 2

Answer:

$=\frac{n(2n-1)(2n+1)}{3}$

Step-by-step explanation:

Here, given series of the question is

$1^{2} +3^{2} +5^{2} +7^{2} +........$upto n terms

and we found the sum of the sq. of odd no.

So, we have the formula for sum of the sq. of odd no.

$=\frac{n(2n-1)(2n+1)}{3}$

but, question did not give the value of n

So that the answer will be in the form of formula

$=\frac{n(2n-1)(2n+1)}{3}$

or we can say that its answer will be infinity.