find the GM where AM and HM are 12 and 3
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step-by-step explanation:
Let the two positive numbers be 'x' and 'y'.
Now,
it is given that,
Arithmetic mean, A.M = 12
=> x + y = 12 × 2
=> x + y = 24..................(i)
Now,
given that,
Harmonic mean, H.M = 3
doing cross multiplication,
we get,
Taking L.C.M of denominators and simplifying,
we get,
But, from eqn (i),
(x+y) = 24,
so putting the value,
we get,
On cross-multiplication,
we get,
But,
we know that,
Geometric mean, G.M of two numbers is the square root of their product.
so,
G.M of 'x' and 'y' is
But,
xy = 36
therefore,
G.M =
=> G.M = 6
Hence,
Geometric mean,G.M of the numbers = 6
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