find the GP in which the 10th 320 and the 6th term is 20
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10th term=ar^9=320. (1)
6th term=ar^5=20. (2)
dividing (1)/(2)
r^4=16
r=2
and a=5/8
6th term=ar^5=20. (2)
dividing (1)/(2)
r^4=16
r=2
and a=5/8
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