Question

find the gradient of a straight line which passes through the point (-4,7) and (2,16)

Answer 1

Answer:

1.5

Step-by-step explanation:

(x1, y1) = (-4, 7)

(x2, y2) = (2, 16)

Gradient m = y2-y1 / x2-x1

m= 16-7 / 2-(-4)

m= 9/6

m= 3/2 = 1.5