Question

find the gradient of curve
y=3x²-5x+4 at point (1,2)
​

Answer 1

Answer:

2=2 L.H.S= R.H.S

Step-by-step explanation:

$y = 3x { }^{2} - 5x + 4 \\ (2) = 3(1) { }^{2} - 5(1) + 4 \\ 2 = 3 - 5 + 4 \\ 2 = 7 - 5 \\ 2 = 2$

I I hope this will help you

Answer 2

The gradient of the given curve y=3x²-5x+4 at point (1,2) is -1

Step-by-step explanation:

Given: y=3x²-5x+4 at point (1,2)

To find: The gradient of the given curve

Solution:

The gradient at a point in a curve is defined as the tangent to that point.

Δf(x,y,x) = δf(x,y,x)/δx + δf(x,y,z)/δy + δf(x,y,z)/δz

Given:

$y = 3x^{2} -7x+2$

$\frac{dy}{dx} = \frac{d(3x^{2} -7x+2)}{dx}$|(1,-2)

$\frac{dy}{dx} = 6x - 7$|(1,-2)

Sub x= 1 and y = -2

$\frac{dy}{dx} = -1$

Therefore,

The gradient of y = -1

Final answer:

The gradient of the given curve is -1

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