Question

Find the gradient of the curve y = 2x^4 + 3t^3 - t + 4 at the points (0, 4) and (1, 8)

Answer 1

Answer:

(t, y) = (0, 4) and (1, 8)? If so, dy/dt = 8t^3 + 9t^2 - 1 at t = 0, dy/dt = -1 at t = 1,

Step-by-step explanation:

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