Question

Find the gradient of the curve y = 2x2 – x + 3 at the point (2 , 5).
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Answer 1

Answer:

Step-by-step explanation:

We have,

$\sf{y=2\,x^2-x+3}$

Differentiating both sides w.r.t x

$\sf{\dfrac{dy}{dx}=2\cdot2x-1}$

$\sf{\implies\,\dfrac{dy}{dx}\bigg|_{x=2}=2\cdot2(2)-1}$

$\sf{\implies\,\dfrac{dy}{dx}\bigg|_{x=2}=8-1=7}$

Answer 2

Answer:

7

Step-by-step explanation:

the gradient of a curve is direvative of the function,

we have,

$y=2x^2 -x+3$

diffrentiating on both sides w.r.t x,

$\dfrac{d}{dx} (2x^2-x+3) =4x -1$

the gradient of the curve y = 2x2 – x + 3 at the point (2 , 5) is,

$4(2)-1= 8-1 \Rightarrow 7$