Question

Find the gradient of the line that is perpendicular to 8y+4x=5

Answer 1

Answer:

Gradient 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope (gradient) and c the y- intercept )

Given

8y + 4x = 5 ( subtract 4x from both sides )

8y = - 4x + 5 ( divide the terms by 8 )

y = - \frac{1}{2}

2

1

x + \frac{5}{8}

8

5

← in slope- intercept form

with gradient = - \frac{1}{2}

2

1

Given a line with gradient m then the gradient of a line perpendicular to it is

m_{perpendicular}m

perpendicular

= - \frac{1}{m}

m

1

= - \frac{1}{-\frac{1}{2} }

−

2

1

1

= 2

Answer 2

Answer:

Step-by-step explanation: