Question

Find the graph where the graph of the equation 3x + 4y=12 cuts x and y axis

Answer 1

The x-axis is where y=0. 
So, let y=0 in your equation and solve for x.
You get -3x-4(0)=-12
-3x=-12
x=4 ; that is the x -intercept.
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Where does the line intersect the y-axis
The y-axis is where x=0.
So let x=0 in your equation and solve for y.
You get -3(0)-4y=-12
-4y=-12
y=3 ; that is the y-intercept
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What is the slope?
To find the slope put the equation in the slope-intercept form
as follows:
-3x-4y=-12
Multiply thru by -1 to get:
3x+4y=12
4y=-3x+12
y=(-3/4)x+3
The slope is -3/4

Answer 2

this is the answer of your question