Question

find the gratest number which divide615 and963 leaving the remainder 6 in each case​

Answer 1

Answer:

87

Step-by-step explanation:

615 - 6 = 609

963 - 6 = 957 (because it leaves a remainder 6)

Factors of:-

609 = 3 x 7 x 29

957 = 3 x 11 x 29

HCF (609, 957) = 3 x 29 = 87

Therefore the gratest number which divide 615 and 963 leaving the remainder 6 is 87.

Answer 2

Answer:

87

Step-by-step explanation:

In this question, since remainder is six ,so we

will subtract 6 from 615 and 963 i.e. 609 and

957 , then, we will find the HCF of 609 and

957, that is going to be our answer.

957=3×11×29

609=3×3×29

so,H.C.F =3×29=87