Question

Find the gravitational force between a man of mass 50 kg and a car of mass 1500 kg separate by 10 m

Answer 1

Answer:

gravitational force =

500.2 X 10 -11 Nm^/kg ^

Answer 2

Answer:

The gravitational force between the man and car is $5.00475 \times 10^{-8}N$.

Explanation:

Given the mass of man, $m_1=50 kg$

Mass of car, $m_2=1500 kg$

Distance of separation, $r=10 m$

• According to Newton's universal law of gravitation, 'the force of attraction  between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them'.
• For the masses of two bodies, $m_1~\&~m_2$, with $r$ as the distance between them, then the force, $F\propto m_1m_2$                   ...(1)

       and $F\propto \dfrac{1}{r^{2} }$                                                                     ...(2)

• Combining (1) and (2),

       $F\propto \dfrac{ m_1m_2}{r^{2} }=G\dfrac{ m_1m_2}{r^{2} }$

• where the proportionality constant is called the gravitational constant, $G= 6.673 \times 10^{-11} N m^2/kg^2$  

Using the given values in the above formula, the gravitational force

$F=\dfrac{ 6.673 \times 10^{-11} \times50\times 1500}{(10)^{2} }$

  $= \dfrac{ 6.673 \times 10^{-8} \times5\times 15}{100} }= 5.00475 \times 10^{-8}N$

Therefore, the gravitational force between the man and car is $5.00475 \times 10^{-8}N$.