find the gravitational force between two petron gift at a separation of one perimeter into 10 to the power minus 15 the mass of photon is 1.67 into 10 to the power minus 27
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Answer:
since F= Gm1 m2
r2
given m1 = m2 = 1.67 * 10^27 kg
r = 10^-15
since, G = 6.67 X 10^-11 nm2 kg^-2
F = 6.67 X 10^-11 nm2 kg^-2 X (1.67 * 10^-27)^2 KG^2
(10^-15)^2 m^2
F = 18.60 X 10^-32N
Step-by-step explanation:
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Answer:
mass=1.67 into 10 to the power minus 27
one perimeter=10 to the power minus 15
now,
F=Gm1m2/r square
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