Question

Find the gravitational force of attraction between a body of unit mass and the Moon. Mass of the moon = 7.4 x 10^22 kg radius of the moon = 1.74 x 10^6 m G = 6.67 x 10^ (-11) Nm^ 2/kg^2

Answer 1

Answer:

On the surface of the moon, the distance to the center of mass is the same as the radius: r=1.74×10

6

m=17,40,000 m. The acceleration due to gravity on the surface of the moon can be found using the formula:

g=

r

2

GM

g=

17400000

(6.673×10

−11

)(7.4×10

22

)

The acceleration due to gravity on the surface of the moon is 1.620 ms

2

.

Answer 2

Given: Mass of the moon = 7.4 x 10^22 kg, radius of the moon = 1.74 x 10^6 m and G = 6.67 x 10^ (-11) Nm^ 2/kg^2

To find: Gravitational force of attraction between a body of unit mass and the Moon

Explanation: Gravitational force of attraction between two masses is always attractive in nature irrespective of the distance and nature.

Let mass of moon be m1 and radius be r.

Mass of unit mass(m2)= 1 kg

The formula for calculating gravitational force of attraction is:

=$\frac{G \times m1 \times \: m2 }{ {r}^{2} }$

=$\frac{6.67 \times {10}^{ - 11} \times 7.4 \times {10}^{22} \times 1 }{ ({1.74 \times {10}^{6} )}^{2} }$

=$\frac{49.358 \times {10}^{11} }{3.02 \times {10}^{12} }$

=$16.34 \times {10}^{ - 1}$

=1.634 N

Therefore, the gravitational force of attraction between a unit mass and the Moon is 1.634 N.