Find the gravitational force of attraction between earth (M=6X1024 kg) and a body of mass 10 kg kept
on its surface. Given R = 6400 km).
Answers
Answer:
Given conditions
Mass of earth (m
1
)=6×10
24
kg
Mass of moon (m
2
)=7.4×10
22
kg
Distance between earth and the moon (d)=3.84×10
5
km
Gravitational constant (G)=6.7×10
−11
Nm
2
/kg using Newton's law of gravitational F=G
d
2
m
1
m
2
F is the force of gravitational between earth and moon
Substituting values in formula F=
(3.84×10
8
)
2
6.7×10
−11
×6×10
24
×7.4×10
22
⇒F=20.1741×10
19
N
⇒F=20.2×10
19
N
Thus the gravitational force of attraction between earth and sun is 2.02×10
19
N.
Answer:
the brainliest answer is wrong the
right answer is
F = Gm1m2 / R²
so
6.67×10^-11 x 6×10^24 × 10 / 6400²
which is 9.8 × 10
we get 98N as the answer
Explanation:
I got it as 9.8 is because that part expect 10 is the formula for g (acceleration due to gravity) which is already 9.8 so 9.8 × 10 we get 98N