Find the great no. That will divide 455,572,699 to leave the remainder 4,5,6
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Subtract each of the remainders with number
445 - 4 = 441
572 - 5 = 567
699 - 6 = 693
Now find the greatest common factor of those 3 numbers:
441 = 3 x 3 x 7 x 7
572 = 3 x 3 x 3 x 3 x 7
693 = 3 x 3 x 7 x 11
The common factors are 3 x 3 x 7 = 63
gcf(441,567,693) = 63
so 63 is the great no. That will divide 455,572,699 to leave the remainder 4,5,6
445 - 4 = 441
572 - 5 = 567
699 - 6 = 693
Now find the greatest common factor of those 3 numbers:
441 = 3 x 3 x 7 x 7
572 = 3 x 3 x 3 x 3 x 7
693 = 3 x 3 x 7 x 11
The common factors are 3 x 3 x 7 = 63
gcf(441,567,693) = 63
so 63 is the great no. That will divide 455,572,699 to leave the remainder 4,5,6
kvnmurty:
it is 567 = 3 x 3 x 3 x 3 x 7 ... not 572
Answered by
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Solutions
In this case, since the numbers 4, 5 and 6 are remainders left after some common number divides 445, 572 and 699 respectively. To solve the problem we have to subtract each of the remainders with number given.
445 - 4 = 441
572 - 5 = 567
699 - 6 = 693
Now find the HCF of 441, 567 and 693.
441 = 7 x 7 x 3 x 3
567 = 7 x 3 x 3 x 3 x 3
693 = 7 x 3 x 3 x 11
Since 7 x 3 x 3 is common across the three numbers, the answer is 63.
In this case, since the numbers 4, 5 and 6 are remainders left after some common number divides 445, 572 and 699 respectively. To solve the problem we have to subtract each of the remainders with number given.
445 - 4 = 441
572 - 5 = 567
699 - 6 = 693
Now find the HCF of 441, 567 and 693.
441 = 7 x 7 x 3 x 3
567 = 7 x 3 x 3 x 3 x 3
693 = 7 x 3 x 3 x 11
Since 7 x 3 x 3 is common across the three numbers, the answer is 63.
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