Math, asked by elangeeraneiarunesh, 6 months ago

Find the great number of five digits which on dividing by 8,16,24,36 and 48 leaves remainder 3 in each case

Answers

Answered by Anonymous
1

\huge { \boxed{ \underline{ \sf{ \orange{Question?}}}}}

Find the great number of five digits which on dividing by 8,16,24,36 and 48 leaves remainder 3 in each case

\huge { \boxed{ \underline{ \sf{ \purple{Answer:- }}}}}</p><p></p><p>

Given:-

  • Numbers:- 8,16,24,36 and 48

To Find:-

  • Find the great number of five digits which on dividing by the numbers given.
  • Remainder:- 3

Solution:-

  • LCM of 8, 16, 24, 36, 48 = 144

  • Greatest 5 digit number = 99999

 \large\implies \mathtt{ \frac{99999}{144} = 63}

  • So to get greatest numbe which is divisible 99999 - 63 = 99936

  • Now we need the number which leaves 3 as reminder so,
  •  \implies \mathtt{99936 + 3 = 99939}
  • \large{ \boxed{ { \sf{ \pink{So, 99939  \: is \:  the \:  greatest  \: 5  \: digit  \: number.  }}}}}</li><li></li><li>

Answered by Anonymous
0

Answer:

Maine

same question solve Kiya h please aap ekk bar Dekh lena answer m okkk

Maybe aapko help mil jaye

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