Math, asked by sagarprasadbhurkunda, 8 months ago

find the greates numbers that divides 57,133 and 384,leaving 7,8 and 9 respectively as remainder.​

Answers

Answered by Anonymous
1

Answer: hope it helps

Step-by-step explanation:

Let say Number = N

N  - 7 = 57A

A - 8 = 133B

B - 9 = 384C

=> B = 384C + 9

=> A - 8 = 133(384C + 9)

=> A = 51072 C  + 1197 + 8

=> A = 51072 C  + 1205

N  - 7 = 57A

=> N - 7  = 57( 51072 C  + 1205)

=> N  = 2911104C  + 68685 + 7

=> N = 2911104C  + 68692

Smallest number = 68692

Answered by 2013purvajadhav
0

Answer:

Let say Number = N

N  - 7 = 57A

A - 8 = 133B

B - 9 = 384C

=> B = 384C + 9

=> A - 8 = 133(384C + 9)

=> A = 51072 C  + 1197 + 8

=> A = 51072 C  + 1205

N  - 7 = 57A

=> N - 7  = 57( 51072 C  + 1205)

=> N  = 2911104C  + 68685 + 7

=> N = 2911104C  + 68692

Smallest number = 68692

Plz mark me as brainliest

Similar questions