Question

Find the greatest 3 digit number that is divisible by both 2 and 3

Answer 1

Hmm!!!!! Your answer is.......☆

999/30=33.3 33 times 30 = 990 is the largest 3-digit number divisible by 2 and. If sum of all digit is divisible by 3 that means those numbers are also divisible by 3. If unit place have even number then its divide by 2.

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Answer 2

Question:-

Find the greatest 3 digit number that is divisible by both 2 and 3.

Answer:-

The number must be less than 1000 and end with a zero and be divisible by 3.

So we start subtracting 10's until we get a number whose digit sum is divisible by 3.

1000 - 10 = 990 and 9 + 9 =18 which is divisible by 3 and 2 so the number is 990.

$\boxed{the \: answer \: is \: 990}$

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