find the greatest 3-digit number that is exactly divisible by 6,15 and 21?
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Question:
find the greatest 3-digit number that is exactly divisible by 6,15 and 21?
Answer:
840
Step-by-step explanation:
To get the required number, we find the LCM of 6, 15 and 21.
LCM = 3x2x5x7 = 210
Now, all the multiples of 210 will be divisible by 6, 15 and 21. These numbers are 210, 420, 630, 840, 1050,.... Thus, the required greatest 3-digit number is 840.
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