Find the greatest 3-digit number which is divisible by 12 ,18 and 24..
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First, let’s remark that any number which is divisible by 24 is divisible by 12. In fact, the unknown number is divisible by the least common multiple of 12, 24 = 2^3 x 3 and 18 = 2 x 3^2, which is 2^3 x 3^2 = 72.
Starting from 720 + 3 x 72 = 936 and seeing that 936+72 > 999, I can tell the answer is 936.
It's correct!!!
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Answer:
936 is the greatest 3-digit number which is divisible by 12 ,18 and 24.
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