Math, asked by Xhxchchvjgj, 1 year ago

Find the greatest 3 digit number which is exactly divisible by 8, 20 and 24

Answers

Answered by Superteen

8 = 2^3
20 = 2^2*5
24 = 2^3*3
LCM = 2^3*3*5
LCM = 120

Greatest 3 digit no.= 999
Greatest 3 digit no. exactly divisible by 8, 20, 24 = 999-remainder of 999/LCM
Remainder of 999/120 = 39

Greatest 3 digit no. divisible by 8, 20 , 24 = 999-39 = 960

Superteen: i can't go into next line

Xhxchchvjgj: Ok

Xhxchchvjgj: Sent

Superteen: when i press ENTER the comment gets posted

Superteen: so i can't write the answer in the comments

Xhxchchvjgj: Sent easy ques so i get point

Superteen: ques?

Superteen: i'll tell you the method. You find yourself

Superteen: you want smallest 4 digit no.?

Xhxchchvjgj: Hi

Answered by riushsarkar

Answer:

8=2×2×2

20=5×2×2

24=3×2×2×2

L.C.M=2×2×2×3×5=120

Greatest 3 digit number=999

Greatest 3 digit number which is exactly divisible by 8,20and24=remainder of 999÷120=39

the number=999-39=960

Previous Question

Next Question