Find the greatest 3-digit number which is exactly divisible by 18, 24, and 30 .
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Answered by
1
Answer:8 = 2^3
20 = 2^2*5
24 = 2^3*3
LCM = 2^3*3*5
LCM = 120
Greatest 3 digit no.= 999
Greatest 3 digit no. exactly divisible by 8, 20, 24 = 999-remainder of 999/LCM
Remainder of 999/120 = 39
Greatest 3 digit no. divisible by 8, 20 , 24 = 999-39 = 960
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Answered by
0
Answer:
720 is exactly divisible by 18, 24, 30
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