Find the greatest 3-digit number which is exactly divisible by 20 and 24 pls solve correctly on a paper
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First we have to find the LCM of 8,20 and 24
∴ LCM of given numbers =2×2××2×3×5=120
Greatest number of 3 digit is 999
We divide 999 by 120 and find the remainder
According to given condition , we need a greatest 3-digit number which is exactly divisible by 120
∴ The required number =999−39=960
hope it will help you ☺
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