Find the greatest 3-digit number which is exactly divisible by 18,24 and 30.
Answers
Answered by
1
we have,
18=2×3×3
24=2×2×2×3
30=2×3×5
HCF =2×3=6
hence 6 is the no. which is easily divisible by 18,24 and 30
hope this helps.
18=2×3×3
24=2×2×2×3
30=2×3×5
HCF =2×3=6
hence 6 is the no. which is easily divisible by 18,24 and 30
hope this helps.
Answered by
2
Step-by-step explanation:
we have
18=2×3×3
24=2×2×2×3
30=2×3×5
LCM=360
360÷999=remainder subtract from 999
the number obtain720
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