Find the greatest 3 digit number which when divided by 75, 45 and 60 leaves:i. no remainder
ii. the remainder 4 in each case.
Answers
Answered by
56
75=3×5275=3×52
45=32×545=32×5
60=22×3×560=22×3×5
LCM (75,45,60)=5^2×3^2×2^2=25×9×4=900
Next number divisible by above three numbers is 1800 ,which is 4 digit
Therefore greatest 3 digit number divisible by all three is 900
Shubham:)
45=32×545=32×5
60=22×3×560=22×3×5
LCM (75,45,60)=5^2×3^2×2^2=25×9×4=900
Next number divisible by above three numbers is 1800 ,which is 4 digit
Therefore greatest 3 digit number divisible by all three is 900
Shubham:)
Answered by
28
Answer:
Step-by-step explanation:
900,904
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