Question

find the greatest 4 digit number which is a perfect square​

Answer 1

Answer=99

$Greatest number of 4-digit =9999,\\ \: We \: find \: \sqrt{9999} \: by \: long \: devsion \: methd$

The reminder is 198,This shows 99² is less then 9999 by 198.

Thus means if we subtract the reminder from the number, we get a perfect square.

Therefore,the required perfect square is 9999-198=9801,

$\sqrt{9801} = 99$

Hence proved!!!

Answer 2

Answer:

9801

Step-by-step explanation:

We know that - Largest 4 digit number is 9999